x^2+14x-127=0

Solution for x^2+14x-127=0 equation:

x^2+14x-127=0

a = 1; b = 14; c = -127;
Δ = b2-4ac
Δ = 142-4·1·(-127)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-8\sqrt{11}}{2*1}=\frac{-14-8\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+8\sqrt{11}}{2*1}=\frac{-14+8\sqrt{11}}{2}
$